Django的SerializerMethodField
1906
2025-03-31
這篇博文將matlab 幫助文檔上的內(nèi)容簡單的貼上,便于我寫其他博文引用,以及查看使用。
impz
Impulse response of digital filter
Syntax
[h,t]?=?impz(b,a)
[h,t] = impz(sos)
[h,t] = impz(d)
[h,t]?=?impz(...,n)
[h,t]?=?impz(...,n,fs)
impz(...)
Description
[h,t] = impz(b,a)returns the impulse response of the filter with numerator coefficients,?b, and denominator coefficients,?a.?impz?chooses the number of samples and returns the response in the column vector,?h, and the sample times in the column vector,?t.?t?=?[0:n-1]'?and?n?=?length(t)?is computed automatically.
[h,t] = impz(sos)returns the impulse response for the second-order sections matrix,?sos.?sos?is a?K-by-6 matrix, where the number of sections,?K, must be greater than or equal to 2. If the number of sections is less than 2,?impz?considers the input to be a numerator vector. Each row of?sos?corresponds to the coefficients of a second order (biquad) filter. The?ith row of the?sos?matrix corresponds to?[bi(1) bi(2) bi(3) ai(1) ai(2) ai(3)].
[h,t] = impz(d)?returns the impulse response of a digital filter,?d. Use?designfilt?to generate?d?based on frequency-response specifications.
[h,t]?=?impz(...,n)?computes?n?samples of the impulse response when?n?is an integer (t?=?[0:n-1]'). If?n?is a vector of integers,?impz?computes the impulse response at those integer locations, starting the response computation from 0 (and?t?=?n?or?t?=?[0 n]). If, instead of?n, you include the empty vector,?[], for the second argument, the number of samples is computed automatically.
[h,t]?=?impz(...,n,fs)?computes?n?samples and produces a vector?t?of length?n?so that the samples are spaced?1/fs?units apart.
impz(...)?with no output arguments plots the impulse response of the filter.
impz?works for both real and complex input systems.
版權(quán)聲明:本文內(nèi)容由網(wǎng)絡(luò)用戶投稿,版權(quán)歸原作者所有,本站不擁有其著作權(quán),亦不承擔(dān)相應(yīng)法律責(zé)任。如果您發(fā)現(xiàn)本站中有涉嫌抄襲或描述失實(shí)的內(nèi)容,請聯(lián)系我們jiasou666@gmail.com 處理,核實(shí)后本網(wǎng)站將在24小時內(nèi)刪除侵權(quán)內(nèi)容。
版權(quán)聲明:本文內(nèi)容由網(wǎng)絡(luò)用戶投稿,版權(quán)歸原作者所有,本站不擁有其著作權(quán),亦不承擔(dān)相應(yīng)法律責(zé)任。如果您發(fā)現(xiàn)本站中有涉嫌抄襲或描述失實(shí)的內(nèi)容,請聯(lián)系我們jiasou666@gmail.com 處理,核實(shí)后本網(wǎng)站將在24小時內(nèi)刪除侵權(quán)內(nèi)容。